2x^2-x-63=10x

Solution for 2x^2-x-63=10x equation:

2x^2-x-63=10x

We move all terms to the left:

2x^2-x-63-(10x)=0

We add all the numbers together, and all the variables

2x^2-11x-63=0

a = 2; b = -11; c = -63;
Δ = b2-4ac
Δ = -112-4·2·(-63)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-25}{2*2}=\frac{-14}{4}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+25}{2*2}=\frac{36}{4}
=9
$